Testing on integer numbers divisibility calculator: tell and explain whether a number is divisible by another

Online calculator: numbers' divisibility check

Integer numbers divisibility:

Approach 1: Divide the numbers and check the remainder of the operation.

Approach 2: Integer numbers prime factorization.

Latest divisibility operations

Number 475,621 is not divisible by 6. Number 475,621 does not have (all) the prime factors of the number 6. Jun 19 04:56 UTC (GMT)
Number 28 is divisible by 2. Number 28 has all the prime factors of the number 2. Jun 19 04:56 UTC (GMT)
Number 2 is not divisible by 16. 2 < 16; 2 cannot be divisible by 16. 2 does not have (all) the prime factors of the number 16. Jun 19 04:54 UTC (GMT)
Number 3,925 is not divisible by 2. Number 3,925 does not have (all) the prime factors of the number 2. Jun 19 04:53 UTC (GMT)
Number 2,964 is divisible by 4. Number 2,964 has all the prime factors of the number 4. Jun 19 04:53 UTC (GMT)
Number 3,366 is divisible by 3. Number 3,366 has all the prime factors of the number 3. Jun 19 04:52 UTC (GMT)
Number 898 is not divisible by 5. Number 898 does not have (all) the prime factors of the number 5. Jun 19 04:51 UTC (GMT)
Number 60 is divisible by 3. Number 60 has all the prime factors of the number 3. Jun 19 04:51 UTC (GMT)
Number 20 is not divisible by 23. 20 < 23; 20 cannot be divisible by 23. 20 does not have (all) the prime factors of the number 23. Jun 19 04:50 UTC (GMT)
Number 106 is not divisible by 7. Number 106 does not have (all) the prime factors of the number 7. Jun 19 04:50 UTC (GMT)
Number 15 is not divisible by 2,809. 15 < 2,809; 15 cannot be divisible by 2,809. 15 does not have (all) the prime factors of the number 2,809. Jun 19 04:50 UTC (GMT)
Number 15 is not divisible by 7. Number 15 does not have (all) the prime factors of the number 7. Jun 19 04:50 UTC (GMT)
Number 342 is divisible by 3. Number 342 has all the prime factors of the number 3. Jun 19 04:50 UTC (GMT)
integer numbers divisibility, see more...

Tutoring: What is the integer numbers divisibility? Divisibility rules.

Divisibility of integer numbers

Let's divide two different numbers, 12 and 15, by 4. When we divide 12 by 4, the quotient is 3 and the operation leaves no remainder. But when we divide 15 by 4, the quotient is 3 and the operation leaves a remainder of 3. We say that the number 12 is divisible by 4 and 15 is not. We also say that 4 is a divisor of 12, but is not a divisor of 15.

In general, we say that "a" is divisible by "b", if there is an integer number "n", so that: a = n × b. Number "b" is called the divisor of "a" ("n" is also a divisor of "a").

0 is divisible by any number other than zero itself.

Any number "a", different of zero, is divisible at least by 1 and itself, which are called improper divisors.

Some divisibility rules

The number 84 is divisible by 4 and 3 and is also divisible by 4 × 3 = 12. This is not true unless the two divisors are coprime.

In general, if "a" is divisible by both "m" and "n" and greatest common factor (m; n) = 1 (coprime numbers), then "a" it is also divisible by their product, (m × n).

Calculating divisors (factors) is very useful when simplifying fractions (reducing fractions to lower terms). The established rules for finding factors (divisors) are based on the fact that the numbers are written in the decimal system. Mutiples of 10 are divisible by 2 and 5, because 10 is divisible by 2 and 5; multiples of 100 are divisible by 4 and 25, because 100 is divisible by 4 and 25; multiples of 1000 are divisible by 8, because 1000 is divisible with 8. All the powers of 10, when divided by 3, or 9, have a remainder equal to 1.

Due to the rules of operation with remainders, we have the following remainders when dividing numbers by 3 or 9: 600 leaves a remainder equal to 6 = 1 × 6; 240 = 2 × 100 + 4 × 10, then the remainder will be equal to 2 × 1 + 4 × 1 = 6. On dividing a number by 3 or 9 the remainder will be equal to that left from dividing the sum of digits of that number by 3 or 9; 7,309 has the sum of the numbers 7 + 3 + 0 + 9 = 19, which is divided without a remainder to neither 3 nor 9. So 7,309 is not divisible by 3 or 9.

All even powers of 10, 100, 10,000, 1,000,000, etc., when divided by 11 left a remainder of 1, and the odd powers of 10, when divided by 11 left a remainder equal to 10 or 10 - 11 = -1. In this case, the alternating sum of the digits bears the same remainder as when dividing by 11, as if the whole number were being divided by 11. How to calculate the alternating sum is shown in the example below.

For instance, for the number: 85,976: 8 + 9 + 6 = 23, 5 + 7 = 12, the alternating sum of the digits: 23 - 12 = 11. So 85,976 is divisible by 11.

A number is divisible by:
  • 2 if the last digit is divisible by 2
  • 4 if the last two digits form a number divisible by 4;
  • 8, if the last three digits form a number divisible by 8;
  • 5 if the last digit is divisible by 5 (5 and 0)
  • 25, if the last two digits form a number divisible by 25
  • 3, if the sum of digits is divisible by 3;
  • 9, if the sum of digits is divisible by 9;
  • 11 if the alternating sum of digits is divisible by 11.