Testing on integer numbers divisibility calculator: tell and explain whether a number is divisible by another

Online calculator: numbers' divisibility check

Integer numbers divisibility:

Approach 1: Divide the numbers and check the remainder of the operation.

Approach 2: Integer numbers prime factorization.

Latest divisibility operations

Number 67 is not divisible by 134. 67 < 134; 67 cannot be divisible by 134. 67 does not have (all) the prime factors of the number 134. Apr 23 08:53 UTC (GMT)
Number 2,500 is not divisible by 9. Number 2,500 does not have (all) the prime factors of the number 9. Apr 23 08:53 UTC (GMT)
Number 208,537 is not divisible by 2. Number 208,537 does not have (all) the prime factors of the number 2. Apr 23 08:53 UTC (GMT)
Number 5,214 is divisible by 2. Number 5,214 has all the prime factors of the number 2. Apr 23 08:52 UTC (GMT)
Number 245 is not divisible by 25. Number 245 does not have (all) the prime factors of the number 25. Apr 23 08:52 UTC (GMT)
Number 9,722 is not divisible by 7. Number 9,722 does not have (all) the prime factors of the number 7. Apr 23 08:52 UTC (GMT)
Number 1,517 is not divisible by 17. Number 1,517 does not have (all) the prime factors of the number 17. Apr 23 08:52 UTC (GMT)
Number 425 is not divisible by 3. Number 425 does not have (all) the prime factors of the number 3. Apr 23 08:52 UTC (GMT)
Number 4,354 is not divisible by 4. Number 4,354 does not have (all) the prime factors of the number 4. Apr 23 08:51 UTC (GMT)
Number 2,691 is divisible by 9. Number 2,691 has all the prime factors of the number 9. Apr 23 08:51 UTC (GMT)
Number 1,620 is not divisible by 7. Number 1,620 does not have (all) the prime factors of the number 7. Apr 23 08:51 UTC (GMT)
Number 247 is divisible by 19. Number 247 has all the prime factors of the number 19. Apr 23 08:51 UTC (GMT)
Number 9,000 is divisible by 5. Number 9,000 has all the prime factors of the number 5. Apr 23 08:49 UTC (GMT)
integer numbers divisibility, see more...

Tutoring: What is the integer numbers divisibility? Divisibility rules.

Divisibility of integer numbers

Let's divide two different numbers, 12 and 15, by 4. When we divide 12 by 4, the quotient is 3 and the operation leaves no remainder. But when we divide 15 by 4, the quotient is 3 and the operation leaves a remainder of 3. We say that the number 12 is divisible by 4 and 15 is not. We also say that 4 is a divisor of 12, but is not a divisor of 15.

In general, we say that "a" is divisible by "b", if there is an integer number "n", so that: a = n × b. Number "b" is called the divisor of "a" ("n" is also a divisor of "a").

0 is divisible by any number other than zero itself.

Any number "a", different of zero, is divisible at least by 1 and itself, which are called improper divisors.

Some divisibility rules

The number 84 is divisible by 4 and 3 and is also divisible by 4 × 3 = 12. This is not true unless the two divisors are coprime.

In general, if "a" is divisible by both "m" and "n" and greatest common factor (m; n) = 1 (coprime numbers), then "a" it is also divisible by their product, (m × n).

Calculating divisors (factors) is very useful when simplifying fractions (reducing fractions to lower terms). The established rules for finding factors (divisors) are based on the fact that the numbers are written in the decimal system. Mutiples of 10 are divisible by 2 and 5, because 10 is divisible by 2 and 5; multiples of 100 are divisible by 4 and 25, because 100 is divisible by 4 and 25; multiples of 1000 are divisible by 8, because 1000 is divisible with 8. All the powers of 10, when divided by 3, or 9, have a remainder equal to 1.

Due to the rules of operation with remainders, we have the following remainders when dividing numbers by 3 or 9: 600 leaves a remainder equal to 6 = 1 × 6; 240 = 2 × 100 + 4 × 10, then the remainder will be equal to 2 × 1 + 4 × 1 = 6. On dividing a number by 3 or 9 the remainder will be equal to that left from dividing the sum of digits of that number by 3 or 9; 7,309 has the sum of the numbers 7 + 3 + 0 + 9 = 19, which is divided without a remainder to neither 3 nor 9. So 7,309 is not divisible by 3 or 9.

All even powers of 10, 100, 10,000, 1,000,000, etc., when divided by 11 left a remainder of 1, and the odd powers of 10, when divided by 11 left a remainder equal to 10 or 10 - 11 = -1. In this case, the alternating sum of the digits bears the same remainder as when dividing by 11, as if the whole number were being divided by 11. How to calculate the alternating sum is shown in the example below.

For instance, for the number: 85,976: 8 + 9 + 6 = 23, 5 + 7 = 12, the alternating sum of the digits: 23 - 12 = 11. So 85,976 is divisible by 11.

A number is divisible by:
  • 2 if the last digit is divisible by 2
  • 4 if the last two digits form a number divisible by 4;
  • 8, if the last three digits form a number divisible by 8;
  • 5 if the last digit is divisible by 5 (5 and 0)
  • 25, if the last two digits form a number divisible by 25
  • 3, if the sum of digits is divisible by 3;
  • 9, if the sum of digits is divisible by 9;
  • 11 if the alternating sum of digits is divisible by 11.